5.20.
Санамсаргүй хэмжигдэхүүний мод ба медианыг ол.
(a) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 1 \\
0,25(-x^2+6x-5) & 1<x\leq 3\\
1 & x>3
\end{array}\right.
$ (b) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 2 \\
0,25(-x^2+8x-12) & 2<x\leq 4\\
1 & x>4
\end{array}\right.
$
(c) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 1 \\
(1/9)(-x^2+8x-7) & 1<x\leq 4\\
1 & x>4
\end{array}\right.
$
(a) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 1 \\
0,25(-x^2+6x-5) & 1<x\leq 3\\
1 & x>3
\end{array}\right.
$ (b) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 2 \\
0,25(-x^2+8x-12) & 2<x\leq 4\\
1 & x>4
\end{array}\right.
$
(c) $F(x)=\left\{\begin{array}{lc}
0 & x\leq 1 \\
(1/9)(-x^2+8x-7) & 1<x\leq 4\\
1 & x>4
\end{array}\right.
$
